Base | Representation |
---|---|
bin | 11001111110001001100100… |
… | …101111110011100110101011 |
3 | 112222102112002002110211022112 |
4 | 121332021210233303212223 |
5 | 104432403224413223223 |
6 | 1042532515143112535 |
7 | 33026161615033463 |
oct | 3176114457634653 |
9 | 488375062424275 |
10 | 114222050523563 |
11 | 33438332837754 |
12 | 10988bb974274b |
13 | 4b9712984a828 |
14 | 202c53bad4ba3 |
15 | d3129e900778 |
hex | 67e264bf39ab |
114222050523563 has 2 divisors, whose sum is σ = 114222050523564. Its totient is φ = 114222050523562.
The previous prime is 114222050523517. The next prime is 114222050523569. The reversal of 114222050523563 is 365325050222411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114222050523563 - 218 = 114222050261419 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 114222050523563.
It is not a weakly prime, because it can be changed into another prime (114222050523569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111025261781 + 57111025261782.
It is an arithmetic number, because the mean of its divisors is an integer number (57111025261782).
Almost surely, 2114222050523563 is an apocalyptic number.
114222050523563 is a deficient number, since it is larger than the sum of its proper divisors (1).
114222050523563 is an equidigital number, since it uses as much as digits as its factorization.
114222050523563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 114222050523563 in words is "one hundred fourteen trillion, two hundred twenty-two billion, fifty million, five hundred twenty-three thousand, five hundred sixty-three".
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