Base | Representation |
---|---|
bin | 11001111110001011100010… |
… | …000001010001010001011011 |
3 | 112222102201111120020202211012 |
4 | 121332023202001101101123 |
5 | 104432422030434103111 |
6 | 1042533503502324135 |
7 | 33026264655324215 |
oct | 3176134201212133 |
9 | 488381446222735 |
10 | 114224152253531 |
11 | 33439211147571 |
12 | 109894a558964b |
13 | 4b973a30c2c28 |
14 | 202c69acb15b5 |
15 | d313741aa48b |
hex | 67e2e205145b |
114224152253531 has 2 divisors, whose sum is σ = 114224152253532. Its totient is φ = 114224152253530.
The previous prime is 114224152253411. The next prime is 114224152253597. The reversal of 114224152253531 is 135352251422411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114224152253531 - 234 = 114206972384347 is a prime.
It is a super-3 number, since 3×1142241522535313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (114224152256531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57112076126765 + 57112076126766.
It is an arithmetic number, because the mean of its divisors is an integer number (57112076126766).
Almost surely, 2114224152253531 is an apocalyptic number.
114224152253531 is a deficient number, since it is larger than the sum of its proper divisors (1).
114224152253531 is an equidigital number, since it uses as much as digits as its factorization.
114224152253531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 288000, while the sum is 41.
The spelling of 114224152253531 in words is "one hundred fourteen trillion, two hundred twenty-four billion, one hundred fifty-two million, two hundred fifty-three thousand, five hundred thirty-one".
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