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114225433 = 716317919
BaseRepresentation
bin1101100111011…
…11000100011001
321221221020211121
412303233010121
5213220203213
615200125241
72554620520
oct663570431
9257836747
10114225433
1159528293
1232306821
131a88471a
14112554b7
15a06488d
hex6cef119

114225433 has 4 divisors (see below), whose sum is σ = 130543360. Its totient is φ = 97907508.

The previous prime is 114225413. The next prime is 114225443. The reversal of 114225433 is 334522411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114225433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114225398 and 114225407.

It is not an unprimeable number, because it can be changed into a prime (114225413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8158953 + ... + 8158966.

It is an arithmetic number, because the mean of its divisors is an integer number (32635840).

Almost surely, 2114225433 is an apocalyptic number.

It is an amenable number.

114225433 is a deficient number, since it is larger than the sum of its proper divisors (16317927).

114225433 is an equidigital number, since it uses as much as digits as its factorization.

114225433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16317926.

The product of its digits is 2880, while the sum is 25.

The square root of 114225433 is about 10687.6299056433. The cubic root of 114225433 is about 485.2001625357.

Adding to 114225433 its reverse (334522411), we get a palindrome (448747844).

The spelling of 114225433 in words is "one hundred fourteen million, two hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 7 16317919 114225433