Base | Representation |
---|---|
bin | 1010011000111001111111… |
… | …1000000011110111100001 |
3 | 1111110000202112101000200021 |
4 | 2212032133320003313201 |
5 | 2444123301040011223 |
6 | 40143353124153441 |
7 | 2256166411420351 |
oct | 246163770036741 |
9 | 44400675330607 |
10 | 11423000313313 |
11 | 3704515975106 |
12 | 1345a2b838881 |
13 | 64b251c01034 |
14 | 2b6c3a2a8b61 |
15 | 14c21242565d |
hex | a639fe03de1 |
11423000313313 has 2 divisors, whose sum is σ = 11423000313314. Its totient is φ = 11423000313312.
The previous prime is 11423000313287. The next prime is 11423000313323. The reversal of 11423000313313 is 31331300032411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6910337077504 + 4512663235809 = 2628752^2 + 2124303^2 .
It is a cyclic number.
It is not a de Polignac number, because 11423000313313 - 217 = 11423000182241 is a prime.
It is not a weakly prime, because it can be changed into another prime (11423000313323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711500156656 + 5711500156657.
It is an arithmetic number, because the mean of its divisors is an integer number (5711500156657).
Almost surely, 211423000313313 is an apocalyptic number.
It is an amenable number.
11423000313313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11423000313313 is an equidigital number, since it uses as much as digits as its factorization.
11423000313313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11423000313313 its reverse (31331300032411), we get a palindrome (42754300345724).
The spelling of 11423000313313 in words is "eleven trillion, four hundred twenty-three billion, three hundred thirteen thousand, three hundred thirteen".
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