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1142311514321 is a prime number
BaseRepresentation
bin10000100111110111000…
…100100111000011010001
311001012111122122101202202
4100213313010213003101
5122203423221424241
62232434244052545
7145346354444105
oct20476704470321
94035448571682
101142311514321
114004a7084a4a
12165479994155
1383947a04893
143d406a5d905
151eaaa380d9b
hex109f71270d1

1142311514321 has 2 divisors, whose sum is σ = 1142311514322. Its totient is φ = 1142311514320.

The previous prime is 1142311514317. The next prime is 1142311514389. The reversal of 1142311514321 is 1234151132411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 642780613696 + 499530900625 = 801736^2 + 706775^2 .

It is an emirp because it is prime and its reverse (1234151132411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1142311514321 - 22 = 1142311514317 is a prime.

It is not a weakly prime, because it can be changed into another prime (1142311510321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571155757160 + 571155757161.

It is an arithmetic number, because the mean of its divisors is an integer number (571155757161).

Almost surely, 21142311514321 is an apocalyptic number.

It is an amenable number.

1142311514321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142311514321 is an equidigital number, since it uses as much as digits as its factorization.

1142311514321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2880, while the sum is 29.

Adding to 1142311514321 its reverse (1234151132411), we get a palindrome (2376462646732).

The spelling of 1142311514321 in words is "one trillion, one hundred forty-two billion, three hundred eleven million, five hundred fourteen thousand, three hundred twenty-one".