Base | Representation |
---|---|
bin | 11001111110010011111000… |
… | …110010101100101111010001 |
3 | 112222110120122211122010120112 |
4 | 121332103320302230233101 |
5 | 104433043414301310213 |
6 | 1042541550043251105 |
7 | 33030033211101125 |
oct | 3176237062545721 |
9 | 488416584563515 |
10 | 114233124244433 |
11 | 33441aa5648087 |
12 | 1098b18a219a95 |
13 | 4b981a2b1749c |
14 | 202ccac6b5585 |
15 | d316ebba2ea8 |
hex | 67e4f8cacbd1 |
114233124244433 has 2 divisors, whose sum is σ = 114233124244434. Its totient is φ = 114233124244432.
The previous prime is 114233124244367. The next prime is 114233124244451. The reversal of 114233124244433 is 334442421332411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64076374771984 + 50156749472449 = 8004772^2 + 7082143^2 .
It is a cyclic number.
It is not a de Polignac number, because 114233124244433 - 28 = 114233124244177 is a prime.
It is not a weakly prime, because it can be changed into another prime (114233124444433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57116562122216 + 57116562122217.
It is an arithmetic number, because the mean of its divisors is an integer number (57116562122217).
Almost surely, 2114233124244433 is an apocalyptic number.
It is an amenable number.
114233124244433 is a deficient number, since it is larger than the sum of its proper divisors (1).
114233124244433 is an equidigital number, since it uses as much as digits as its factorization.
114233124244433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 663552, while the sum is 41.
Adding to 114233124244433 its reverse (334442421332411), we get a palindrome (448675545576844).
The spelling of 114233124244433 in words is "one hundred fourteen trillion, two hundred thirty-three billion, one hundred twenty-four million, two hundred forty-four thousand, four hundred thirty-three".
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