Search a number
-
+
114233124244433 is a prime number
BaseRepresentation
bin11001111110010011111000…
…110010101100101111010001
3112222110120122211122010120112
4121332103320302230233101
5104433043414301310213
61042541550043251105
733030033211101125
oct3176237062545721
9488416584563515
10114233124244433
1133441aa5648087
121098b18a219a95
134b981a2b1749c
14202ccac6b5585
15d316ebba2ea8
hex67e4f8cacbd1

114233124244433 has 2 divisors, whose sum is σ = 114233124244434. Its totient is φ = 114233124244432.

The previous prime is 114233124244367. The next prime is 114233124244451. The reversal of 114233124244433 is 334442421332411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64076374771984 + 50156749472449 = 8004772^2 + 7082143^2 .

It is a cyclic number.

It is not a de Polignac number, because 114233124244433 - 28 = 114233124244177 is a prime.

It is not a weakly prime, because it can be changed into another prime (114233124444433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57116562122216 + 57116562122217.

It is an arithmetic number, because the mean of its divisors is an integer number (57116562122217).

Almost surely, 2114233124244433 is an apocalyptic number.

It is an amenable number.

114233124244433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114233124244433 is an equidigital number, since it uses as much as digits as its factorization.

114233124244433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 663552, while the sum is 41.

Adding to 114233124244433 its reverse (334442421332411), we get a palindrome (448675545576844).

The spelling of 114233124244433 in words is "one hundred fourteen trillion, two hundred thirty-three billion, one hundred twenty-four million, two hundred forty-four thousand, four hundred thirty-three".