Base | Representation |
---|---|
bin | 11001111110010011111001… |
… | …001000101000100110011001 |
3 | 112222110120200020110021101111 |
4 | 121332103321020220212121 |
5 | 104433043422234312044 |
6 | 1042541550410420321 |
7 | 33030033311010451 |
oct | 3176237110504631 |
9 | 488416606407344 |
10 | 114233129994649 |
11 | 33441aa8915326 |
12 | 1098b1901316a1 |
13 | 4b981a407b893 |
14 | 202ccad370d61 |
15 | d316ec43bb34 |
hex | 67e4f9228999 |
114233129994649 has 2 divisors, whose sum is σ = 114233129994650. Its totient is φ = 114233129994648.
The previous prime is 114233129994617. The next prime is 114233129994667. The reversal of 114233129994649 is 946499921332411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95817316431424 + 18415813563225 = 9788632^2 + 4291365^2 .
It is a cyclic number.
It is not a de Polignac number, because 114233129994649 - 25 = 114233129994617 is a prime.
It is not a weakly prime, because it can be changed into another prime (114233129914649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57116564997324 + 57116564997325.
It is an arithmetic number, because the mean of its divisors is an integer number (57116564997325).
Almost surely, 2114233129994649 is an apocalyptic number.
It is an amenable number.
114233129994649 is a deficient number, since it is larger than the sum of its proper divisors (1).
114233129994649 is an equidigital number, since it uses as much as digits as its factorization.
114233129994649 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90699264, while the sum is 67.
The spelling of 114233129994649 in words is "one hundred fourteen trillion, two hundred thirty-three billion, one hundred twenty-nine million, nine hundred ninety-four thousand, six hundred forty-nine".
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