Base | Representation |
---|---|
bin | 11001111110011010010011… |
… | …110100000001000010010011 |
3 | 112222111020110102021002211222 |
4 | 121332122103310001002103 |
5 | 104433202030111303431 |
6 | 1042545050215555255 |
7 | 33030366123214103 |
oct | 3176322364010223 |
9 | 488436412232758 |
10 | 114240020025491 |
11 | 33444a14089498 |
12 | 1099059368bb2b |
13 | 4b98a316604c9 |
14 | 202d364463203 |
15 | d319a228257b |
hex | 67e693d01093 |
114240020025491 has 2 divisors, whose sum is σ = 114240020025492. Its totient is φ = 114240020025490.
The previous prime is 114240020025463. The next prime is 114240020025559. The reversal of 114240020025491 is 194520020042411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114240020025491 - 214 = 114240020009107 is a prime.
It is a super-3 number, since 3×1142400200254913 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (114240020325491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120010012745 + 57120010012746.
It is an arithmetic number, because the mean of its divisors is an integer number (57120010012746).
Almost surely, 2114240020025491 is an apocalyptic number.
114240020025491 is a deficient number, since it is larger than the sum of its proper divisors (1).
114240020025491 is an equidigital number, since it uses as much as digits as its factorization.
114240020025491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 35.
The spelling of 114240020025491 in words is "one hundred fourteen trillion, two hundred forty billion, twenty million, twenty-five thousand, four hundred ninety-one".
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