Base | Representation |
---|---|
bin | 10101010001110110… |
… | …11111010000011001 |
3 | 1002111011110110222201 |
4 | 22220323133100121 |
5 | 141344032221101 |
6 | 5125334050201 |
7 | 553046155036 |
oct | 125073372031 |
9 | 32434413881 |
10 | 11424101401 |
11 | 4932675519 |
12 | 2269aa9961 |
13 | 1100a5711b |
14 | 7a534a38d |
15 | 46ce13e01 |
hex | 2a8edf419 |
11424101401 has 2 divisors, whose sum is σ = 11424101402. Its totient is φ = 11424101400.
The previous prime is 11424101387. The next prime is 11424101527. The reversal of 11424101401 is 10410142411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6076982025 + 5347119376 = 77955^2 + 73124^2 .
It is an emirp because it is prime and its reverse (10410142411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11424101401 - 213 = 11424093209 is a prime.
It is not a weakly prime, because it can be changed into another prime (11424701401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712050700 + 5712050701.
It is an arithmetic number, because the mean of its divisors is an integer number (5712050701).
Almost surely, 211424101401 is an apocalyptic number.
It is an amenable number.
11424101401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11424101401 is an equidigital number, since it uses as much as digits as its factorization.
11424101401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 11424101401 its reverse (10410142411), we get a palindrome (21834243812).
The spelling of 11424101401 in words is "eleven billion, four hundred twenty-four million, one hundred one thousand, four hundred one".
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