Base | Representation |
---|---|
bin | 11001111110011011001111… |
… | …000101000010110101101011 |
3 | 112222111100000201020202212221 |
4 | 121332123033011002311223 |
5 | 104433211044133020232 |
6 | 1042545333015414511 |
7 | 33030432555616021 |
oct | 3176331705026553 |
9 | 488440021222787 |
10 | 114241014345067 |
11 | 33445384382505 |
12 | 10990810684437 |
13 | 4b98b5c65bc9c |
14 | 202d41a532711 |
15 | d31a0e6e0897 |
hex | 67e6cf142d6b |
114241014345067 has 2 divisors, whose sum is σ = 114241014345068. Its totient is φ = 114241014345066.
The previous prime is 114241014344959. The next prime is 114241014345121. The reversal of 114241014345067 is 760543410142411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114241014345067 is a prime.
It is not a weakly prime, because it can be changed into another prime (114241014345467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120507172533 + 57120507172534.
It is an arithmetic number, because the mean of its divisors is an integer number (57120507172534).
Almost surely, 2114241014345067 is an apocalyptic number.
114241014345067 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241014345067 is an equidigital number, since it uses as much as digits as its factorization.
114241014345067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 43.
Adding to 114241014345067 its reverse (760543410142411), we get a palindrome (874784424487478).
The spelling of 114241014345067 in words is "one hundred fourteen trillion, two hundred forty-one billion, fourteen million, three hundred forty-five thousand, sixty-seven".
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