Base | Representation |
---|---|
bin | 11001111110011011010001… |
… | …010010001110001111000011 |
3 | 112222111100010021220000200001 |
4 | 121332123101102032033003 |
5 | 104433211133121312201 |
6 | 1042545340420540431 |
7 | 33030433515315646 |
oct | 3176332122161703 |
9 | 488440107800601 |
10 | 114241051354051 |
11 | 334453a325a946 |
12 | 10990820b51717 |
13 | 4b98b672192ab |
14 | 202d421407a5d |
15 | d31a12aa1301 |
hex | 67e6d148e3c3 |
114241051354051 has 2 divisors, whose sum is σ = 114241051354052. Its totient is φ = 114241051354050.
The previous prime is 114241051354043. The next prime is 114241051354097. The reversal of 114241051354051 is 150453150142411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114241051354051 - 23 = 114241051354043 is a prime.
It is a super-4 number, since 4×1142410513540514 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 114241051354051.
It is not a weakly prime, because it can be changed into another prime (114241051324051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120525677025 + 57120525677026.
It is an arithmetic number, because the mean of its divisors is an integer number (57120525677026).
Almost surely, 2114241051354051 is an apocalyptic number.
114241051354051 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241051354051 is an equidigital number, since it uses as much as digits as its factorization.
114241051354051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48000, while the sum is 37.
The spelling of 114241051354051 in words is "one hundred fourteen trillion, two hundred forty-one billion, fifty-one million, three hundred fifty-four thousand, fifty-one".
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