114241140351131 has 4 divisors (see below), whose sum is σ = 114327752286000. Its totient is φ = 114154528416264.

The previous prime is 114241140351103. The next prime is 114241140351167. The reversal of 114241140351131 is 131153041142411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114241140351131 is a prime.

It is a super-2 number, since 2×114241140351131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114241140351181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43305965456 + ... + 43305968093.

It is an arithmetic number, because the mean of its divisors is an integer number (28581938071500).

Almost surely, 2^{114241140351131} is an apocalyptic number.

114241140351131 is a deficient number, since it is larger than the sum of its proper divisors (86611934869).

114241140351131 is an equidigital number, since it uses as much as digits as its factorization.

114241140351131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86611934868.

The product of its (nonzero) digits is 5760, while the sum is 32.

Adding to 114241140351131 its reverse (131153041142411), we get a palindrome (245394181493542).

The spelling of 114241140351131 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred forty million, three hundred fifty-one thousand, one hundred thirty-one".