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114241420132000 = 2553723331748843
BaseRepresentation
bin11001111110011011100111…
…010000111111111010100000
3112222111101001222210212220121
4121332123213100333322200
5104433212412023211000
61042545441153050024
733030445614012220
oct3176334720777240
9488441058725817
10114241420132000
1133445572440207
1210990904556914
134b98bc57485b5
14202d4583a2080
15d31a35148b1a
hex67e6e743fea0

114241420132000 has 192 divisors, whose sum is σ = 320927592271104. Its totient is φ = 39151675622400.

The previous prime is 114241420131997. The next prime is 114241420132001. The reversal of 114241420132000 is 231024142411.

It is a super-2 number, since 2×1142414201320002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (114241420132001) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 64449579 + ... + 66198421.

It is an arithmetic number, because the mean of its divisors is an integer number (1671497876412).

Almost surely, 2114241420132000 is an apocalyptic number.

114241420132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 114241420132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (160463796135552).

114241420132000 is an abundant number, since it is smaller than the sum of its proper divisors (206686172139104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114241420132000 is a wasteful number, since it uses less digits than its factorization.

114241420132000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1751208 (or 1751190 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 114241420132000 its reverse (231024142411), we get a palindrome (114472444274411).

The spelling of 114241420132000 in words is "one hundred fourteen trillion, two hundred forty-one billion, four hundred twenty million, one hundred thirty-two thousand".