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114242134154441 is a prime number
BaseRepresentation
bin11001111110011100010001…
…110100110001110011001001
3112222111102220202100222120012
4121332130101310301303021
5104433220342320420231
61042550040101041305
733030502404055256
oct3176342164616311
9488442822328505
10114242134154441
11334458a94978a7
1210990a836b6235
134b98caa657397
14202d4c514a42d
15d31a77b8ae2b
hex67e711d31cc9

114242134154441 has 2 divisors, whose sum is σ = 114242134154442. Its totient is φ = 114242134154440.

The previous prime is 114242134154389. The next prime is 114242134154471. The reversal of 114242134154441 is 144451431242411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112490736007225 + 1751398147216 = 10606165^2 + 1323404^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114242134154441 is a prime.

It is a super-2 number, since 2×1142421341544412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114242134154471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121067077220 + 57121067077221.

It is an arithmetic number, because the mean of its divisors is an integer number (57121067077221).

Almost surely, 2114242134154441 is an apocalyptic number.

It is an amenable number.

114242134154441 is a deficient number, since it is larger than the sum of its proper divisors (1).

114242134154441 is an equidigital number, since it uses as much as digits as its factorization.

114242134154441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 245760, while the sum is 41.

Adding to 114242134154441 its reverse (144451431242411), we get a palindrome (258693565396852).

The spelling of 114242134154441 in words is "one hundred fourteen trillion, two hundred forty-two billion, one hundred thirty-four million, one hundred fifty-four thousand, four hundred forty-one".