Base | Representation |
---|---|
bin | 10000100111111110011… |
… | …001001010000111000010 |
3 | 11001012211012202122201122 |
4 | 100213332121022013002 |
5 | 122204201142410224 |
6 | 2232454352432242 |
7 | 145352405451230 |
oct | 20477631120702 |
9 | 4035735678648 |
10 | 1142434341314 |
11 | 40055a447762 |
12 | 1654b2b48682 |
13 | 839672ab486 |
14 | 3d4190b3950 |
15 | 1eab604415e |
hex | 109fe64a1c2 |
1142434341314 has 16 divisors (see below), whose sum is σ = 2043609257088. Its totient is φ = 468327121152.
The previous prime is 1142434341311. The next prime is 1142434341319. The reversal of 1142434341314 is 4131434342411.
It is a super-3 number, since 3×11424343413143 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1142434341311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1773966047 + ... + 1773966690.
It is an arithmetic number, because the mean of its divisors is an integer number (127725578568).
Almost surely, 21142434341314 is an apocalyptic number.
1142434341314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1142434341314 is a deficient number, since it is larger than the sum of its proper divisors (901174915774).
1142434341314 is a wasteful number, since it uses less digits than its factorization.
1142434341314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3547932769.
The product of its digits is 55296, while the sum is 35.
Adding to 1142434341314 its reverse (4131434342411), we get a palindrome (5273868683725).
The spelling of 1142434341314 in words is "one trillion, one hundred forty-two billion, four hundred thirty-four million, three hundred forty-one thousand, three hundred fourteen".
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