114244043040441 has 24 divisors (see below), whose sum is σ = 166603036236000. Its totient is φ = 75434297127552.

The previous prime is 114244043040397. The next prime is 114244043040581. The reversal of 114244043040441 is 144040340442411.

114244043040441 is a `hidden beast` number, since 1 + 1 + 4 + 244 + 0 + 4 + 3 + 0 + 404 + 4 + 1 = 666.

It is not a de Polignac number, because 114244043040441 - 2¹¹ = 114244043038393 is a prime.

It is a super-2 number, since 2×114244043040441² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114244043040396 and 114244043040405.

It is not an unprimeable number, because it can be changed into a prime (114244043040341) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 108452176 + ... + 109500513.

It is an arithmetic number, because the mean of its divisors is an integer number (6941793176500).

Almost surely, 2^{114244043040441} is an apocalyptic number.

It is an amenable number.

114244043040441 is a deficient number, since it is larger than the sum of its proper divisors (52358993195559).

114244043040441 is a wasteful number, since it uses less digits than its factorization.

114244043040441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 217953253 (or 217953250 counting only the distinct ones).

The product of its (nonzero) digits is 98304, while the sum is 36.

Adding to 114244043040441 its reverse (144040340442411), we get a palindrome (258284383482852).

The spelling of 114244043040441 in words is "one hundred fourteen trillion, two hundred forty-four billion, forty-three million, forty thousand, four hundred forty-one".