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1142532424153 = 6358717968019
BaseRepresentation
bin10000101000000100001…
…111010100000111011001
311001020002001022210002101
4100220010033110013121
5122204401300033103
62232512215003401
7145355006240101
oct20500417240731
94036061283071
101142532424153
114005aa84985a
1216551b969561
1383981700463
143d428126201
151eabe96aa1d
hex10a043d41d9

1142532424153 has 4 divisors (see below), whose sum is σ = 1142550455760. Its totient is φ = 1142514392548.

The previous prime is 1142532424151. The next prime is 1142532424277. The reversal of 1142532424153 is 3514242352411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1142532424153 - 21 = 1142532424151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1142532424151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8920423 + ... + 9047596.

It is an arithmetic number, because the mean of its divisors is an integer number (285637613940).

Almost surely, 21142532424153 is an apocalyptic number.

It is an amenable number.

1142532424153 is a deficient number, since it is larger than the sum of its proper divisors (18031607).

1142532424153 is an equidigital number, since it uses as much as digits as its factorization.

1142532424153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18031606.

The product of its digits is 115200, while the sum is 37.

Adding to 1142532424153 its reverse (3514242352411), we get a palindrome (4656774776564).

The spelling of 1142532424153 in words is "one trillion, one hundred forty-two billion, five hundred thirty-two million, four hundred twenty-four thousand, one hundred fifty-three".

Divisors: 1 63587 17968019 1142532424153