Base | Representation |
---|---|
bin | 11001111110100111010110… |
… | …111001100001000000110011 |
3 | 112222112120121211100000221101 |
4 | 121332213112321201000303 |
5 | 104433414223243130142 |
6 | 1042555324343505231 |
7 | 33031403245620052 |
oct | 3176472671410063 |
9 | 488476554300841 |
10 | 114254030442547 |
11 | 3344a953652166 |
12 | 10993243758217 |
13 | 4b9a155178a08 |
14 | 202dcd308c399 |
15 | d320222720b7 |
hex | 67e9d6e61033 |
114254030442547 has 2 divisors, whose sum is σ = 114254030442548. Its totient is φ = 114254030442546.
The previous prime is 114254030442521. The next prime is 114254030442641. The reversal of 114254030442547 is 745244030452411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114254030442547 - 211 = 114254030440499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114254030442497 and 114254030442506.
It is not a weakly prime, because it can be changed into another prime (114254030442247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127015221273 + 57127015221274.
It is an arithmetic number, because the mean of its divisors is an integer number (57127015221274).
Almost surely, 2114254030442547 is an apocalyptic number.
114254030442547 is a deficient number, since it is larger than the sum of its proper divisors (1).
114254030442547 is an equidigital number, since it uses as much as digits as its factorization.
114254030442547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2150400, while the sum is 46.
Adding to 114254030442547 its reverse (745244030452411), we get a palindrome (859498060894958).
The spelling of 114254030442547 in words is "one hundred fourteen trillion, two hundred fifty-four billion, thirty million, four hundred forty-two thousand, five hundred forty-seven".
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