Base | Representation |
---|---|
bin | 11001111110100111011011… |
… | …001011000010011111101010 |
3 | 112222112120210211020220012212 |
4 | 121332213123023002133222 |
5 | 104433414400122120002 |
6 | 1042555335424405122 |
7 | 33031405106234111 |
oct | 3176473313023752 |
9 | 488476724226185 |
10 | 114254102145002 |
11 | 3344a990076296 |
12 | 109932637767a2 |
13 | 4b9a166c923c1 |
14 | 202dcdc7d4c78 |
15 | d320286d7352 |
hex | 67e9db2c27ea |
114254102145002 has 4 divisors (see below), whose sum is σ = 171381153217506. Its totient is φ = 57127051072500.
The previous prime is 114254102144999. The next prime is 114254102145019. The reversal of 114254102145002 is 200541201452411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 95668958664601 + 18585143480401 = 9781051^2 + 4311049^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 114254102145002.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28563525536249 + ... + 28563525536252.
Almost surely, 2114254102145002 is an apocalyptic number.
114254102145002 is a deficient number, since it is larger than the sum of its proper divisors (57127051072504).
114254102145002 is an equidigital number, since it uses as much as digits as its factorization.
114254102145002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57127051072503.
The product of its (nonzero) digits is 12800, while the sum is 32.
Adding to 114254102145002 its reverse (200541201452411), we get a palindrome (314795303597413).
The spelling of 114254102145002 in words is "one hundred fourteen trillion, two hundred fifty-four billion, one hundred two million, one hundred forty-five thousand, two".
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