Base | Representation |
---|---|
bin | 11001111110100111011011… |
… | …010011101011100100100001 |
3 | 112222112120210222111222202112 |
4 | 121332213123103223210201 |
5 | 104433414401212113101 |
6 | 1042555335545125105 |
7 | 33031405134420554 |
oct | 3176473323534441 |
9 | 488476728458675 |
10 | 114254104410401 |
11 | 3344a99138331a |
12 | 10993264489795 |
13 | 4b9a1675a6587 |
14 | 202dcdcc2469b |
15 | d320289d36bb |
hex | 67e9db4eb921 |
114254104410401 has 2 divisors, whose sum is σ = 114254104410402. Its totient is φ = 114254104410400.
The previous prime is 114254104410377. The next prime is 114254104410409. The reversal of 114254104410401 is 104014401452411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85037906560000 + 29216197850401 = 9221600^2 + 5405201^2 .
It is a cyclic number.
It is not a de Polignac number, because 114254104410401 - 230 = 114253030668577 is a prime.
It is not a weakly prime, because it can be changed into another prime (114254104410409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127052205200 + 57127052205201.
It is an arithmetic number, because the mean of its divisors is an integer number (57127052205201).
Almost surely, 2114254104410401 is an apocalyptic number.
It is an amenable number.
114254104410401 is a deficient number, since it is larger than the sum of its proper divisors (1).
114254104410401 is an equidigital number, since it uses as much as digits as its factorization.
114254104410401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10240, while the sum is 32.
Adding to 114254104410401 its reverse (104014401452411), we get a palindrome (218268505862812).
The spelling of 114254104410401 in words is "one hundred fourteen trillion, two hundred fifty-four billion, one hundred four million, four hundred ten thousand, four hundred one".
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