114254141420137 has 2 divisors, whose sum is σ = 114254141420138. Its totient is φ = 114254141420136.

The previous prime is 114254141420117. The next prime is 114254141420147. The reversal of 114254141420137 is 731024141452411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114050353278096 + 203788142041 = 10679436^2 + 451429^2 .

It is an emirp because it is prime and its reverse (731024141452411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114254141420137 - 2¹¹ = 114254141418089 is a prime.

It is a super-2 number, since 2×114254141420137² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114254141420137.

It is not a weakly prime, because it can be changed into another prime (114254141420117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127070710068 + 57127070710069.

It is an arithmetic number, because the mean of its divisors is an integer number (57127070710069).

Almost surely, 2^{114254141420137} is an apocalyptic number.

It is an amenable number.

114254141420137 is a deficient number, since it is larger than the sum of its proper divisors (1).

114254141420137 is an equidigital number, since it uses as much as digits as its factorization.

114254141420137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 107520, while the sum is 40.

Adding to 114254141420137 its reverse (731024141452411), we get a palindrome (845278282872548).

The spelling of 114254141420137 in words is "one hundred fourteen trillion, two hundred fifty-four billion, one hundred forty-one million, four hundred twenty thousand, one hundred thirty-seven".