114255100402033 has 4 divisors (see below), whose sum is σ = 114321412127728. Its totient is φ = 114188788676340.

The previous prime is 114255100401991. The next prime is 114255100402043. The reversal of 114255100402033 is 330204001552411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114255100402033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114255100401986 and 114255100402004.

It is not an unprimeable number, because it can be changed into a prime (114255100402043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33155860263 + ... + 33155863708.

It is an arithmetic number, because the mean of its divisors is an integer number (28580353031932).

Almost surely, 2^{114255100402033} is an apocalyptic number.

It is an amenable number.

114255100402033 is a deficient number, since it is larger than the sum of its proper divisors (66311725695).

114255100402033 is an equidigital number, since it uses as much as digits as its factorization.

114255100402033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66311725694.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 114255100402033 its reverse (330204001552411), we get a palindrome (444459101954444).

The spelling of 114255100402033 in words is "one hundred fourteen trillion, two hundred fifty-five billion, one hundred million, four hundred two thousand, thirty-three".