Base | Representation |
---|---|
bin | 11001111110101000010110… |
… | …110101011111101100100010 |
3 | 112222112200101120210020001012 |
4 | 121332220112311133230202 |
5 | 104433423422400133102 |
6 | 1043000023023140522 |
7 | 33031441652410643 |
oct | 3176502665375442 |
9 | 488480346706035 |
10 | 114255103130402 |
11 | 33450354102453 |
12 | 109934a2a44742 |
13 | 4b9a296485c60 |
14 | 202dd9571b6ca |
15 | d32086510752 |
hex | 67ea16d5fb22 |
114255103130402 has 16 divisors (see below), whose sum is σ = 184588758712512. Its totient is φ = 52726603697040.
The previous prime is 114255103130309. The next prime is 114255103130417. The reversal of 114255103130402 is 204031301552411.
114255103130402 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1142551031304023 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 271486724 + ... + 271907247.
It is an arithmetic number, because the mean of its divisors is an integer number (11536797419532).
Almost surely, 2114255103130402 is an apocalyptic number.
114255103130402 is a deficient number, since it is larger than the sum of its proper divisors (70333655582110).
114255103130402 is a wasteful number, since it uses less digits than its factorization.
114255103130402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 543402073.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 114255103130402 its reverse (204031301552411), we get a palindrome (318286404682813).
The spelling of 114255103130402 in words is "one hundred fourteen trillion, two hundred fifty-five billion, one hundred three million, one hundred thirty thousand, four hundred two".
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