Search a number
-
+
1142555054131 = 8071931415467
BaseRepresentation
bin10000101000000101100…
…101101001000000110011
311001020010121220111120201
4100220011211221000303
5122204423043213011
62232514344020031
7145355402501521
oct20500545510063
94036117814521
101142555054131
114006115a6017
12165527461617
13839862c498a
143d42b137311
151eac193acc1
hex10a05969033

1142555054131 has 4 divisors (see below), whose sum is σ = 1142557276792. Its totient is φ = 1142552831472.

The previous prime is 1142555054117. The next prime is 1142555054149. The reversal of 1142555054131 is 1314505552411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1142555054131 is a prime.

It is a super-2 number, since 2×11425550541312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1142555054171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99460 + ... + 1514926.

It is an arithmetic number, because the mean of its divisors is an integer number (285639319198).

Almost surely, 21142555054131 is an apocalyptic number.

1142555054131 is a deficient number, since it is larger than the sum of its proper divisors (2222661).

1142555054131 is an equidigital number, since it uses as much as digits as its factorization.

1142555054131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2222660.

The product of its (nonzero) digits is 60000, while the sum is 37.

The spelling of 1142555054131 in words is "one trillion, one hundred forty-two billion, five hundred fifty-five million, fifty-four thousand, one hundred thirty-one".

Divisors: 1 807193 1415467 1142555054131