Base | Representation |
---|---|
bin | 110101001101010100… |
… | …0100100001100000011 |
3 | 101220221012212221111121 |
4 | 1222122220210030003 |
5 | 3333002422144242 |
6 | 124254130453111 |
7 | 11153361340366 |
oct | 1523250441403 |
9 | 356835787447 |
10 | 114263474947 |
11 | 44505830a26 |
12 | 1a18a734197 |
13 | aa0c89b44b |
14 | 575d5200dd |
15 | 2e8b564667 |
hex | 1a9aa24303 |
114263474947 has 2 divisors, whose sum is σ = 114263474948. Its totient is φ = 114263474946.
The previous prime is 114263474903. The next prime is 114263474971. The reversal of 114263474947 is 749474362411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114263474947 is a prime.
It is a super-2 number, since 2×1142634749472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114263474894 and 114263474903.
It is not a weakly prime, because it can be changed into another prime (114263474987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57131737473 + 57131737474.
It is an arithmetic number, because the mean of its divisors is an integer number (57131737474).
Almost surely, 2114263474947 is an apocalyptic number.
114263474947 is a deficient number, since it is larger than the sum of its proper divisors (1).
114263474947 is an equidigital number, since it uses as much as digits as its factorization.
114263474947 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4064256, while the sum is 52.
The spelling of 114263474947 in words is "one hundred fourteen billion, two hundred sixty-three million, four hundred seventy-four thousand, nine hundred forty-seven".
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