Base | Representation |
---|---|
bin | 11001111111010010001100… |
… | …001010001001110101011001 |
3 | 112222200222022222222012101222 |
4 | 121333102030022021311121 |
5 | 104440142420403344423 |
6 | 1043032412124221425 |
7 | 33034622035326245 |
oct | 3177221412116531 |
9 | 488628288865358 |
10 | 114300021153113 |
11 | 33468404166774 |
12 | 109a013999a875 |
13 | 4ba15a43c3a13 |
14 | 203221712b425 |
15 | d33314b593c8 |
hex | 67f48c289d59 |
114300021153113 has 2 divisors, whose sum is σ = 114300021153114. Its totient is φ = 114300021153112.
The previous prime is 114300021153091. The next prime is 114300021153223. The reversal of 114300021153113 is 311351120003411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109860521584969 + 4439499568144 = 10481437^2 + 2107012^2 .
It is a cyclic number.
It is not a de Polignac number, because 114300021153113 - 214 = 114300021136729 is a prime.
It is not a weakly prime, because it can be changed into another prime (114300021153313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150010576556 + 57150010576557.
It is an arithmetic number, because the mean of its divisors is an integer number (57150010576557).
Almost surely, 2114300021153113 is an apocalyptic number.
It is an amenable number.
114300021153113 is a deficient number, since it is larger than the sum of its proper divisors (1).
114300021153113 is an equidigital number, since it uses as much as digits as its factorization.
114300021153113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 26.
Adding to 114300021153113 its reverse (311351120003411), we get a palindrome (425651141156524).
The spelling of 114300021153113 in words is "one hundred fourteen trillion, three hundred billion, twenty-one million, one hundred fifty-three thousand, one hundred thirteen".
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