114300021434233 has 4 divisors (see below), whose sum is σ = 114300046998900. Its totient is φ = 114299995869568.

The previous prime is 114300021434213. The next prime is 114300021434281. The reversal of 114300021434233 is 332434120003411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 62490084274489 + 51809937159744 = 7905067^2 + 7197912^2 .

It is a cyclic number.

It is not a de Polignac number, because 114300021434233 - 2³⁷ = 114162582480761 is a prime.

It is a super-2 number, since 2×114300021434233² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114300021434195 and 114300021434204.

It is not an unprimeable number, because it can be changed into a prime (114300021434213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4118260 + ... + 15670357.

It is an arithmetic number, because the mean of its divisors is an integer number (28575011749725).

Almost surely, 2^{114300021434233} is an apocalyptic number.

It is an amenable number.

114300021434233 is a deficient number, since it is larger than the sum of its proper divisors (25564667).

114300021434233 is an equidigital number, since it uses as much as digits as its factorization.

114300021434233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25564666.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 114300021434233 its reverse (332434120003411), we get a palindrome (446734141437644).

The spelling of 114300021434233 in words is "one hundred fourteen trillion, three hundred billion, twenty-one million, four hundred thirty-four thousand, two hundred thirty-three".