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114301141113453 = 3719286469025347
BaseRepresentation
bin11001111111010011001110…
…111010011101101001101101
3112222201002020001101002011120
4121333103032322131221231
5104440202214111112303
61043033115213011153
733034661554664610
oct3177231672355155
9488632201332146
10114301141113453
1133468929374528
12109a03b0a83ab9
134ba1722442a48
1420322c1b84177
15d3337d134553
hex67f4cee9da6d

114301141113453 has 16 divisors (see below), whose sum is σ = 183340176222720. Its totient is φ = 61877309474736.

The previous prime is 114301141113421. The next prime is 114301141113487. The reversal of 114301141113453 is 354311141103411.

It is not a de Polignac number, because 114301141113453 - 25 = 114301141113421 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114301141123453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 143234512275 + ... + 143234513072.

It is an arithmetic number, because the mean of its divisors is an integer number (11458761013920).

Almost surely, 2114301141113453 is an apocalyptic number.

It is an amenable number.

114301141113453 is a deficient number, since it is larger than the sum of its proper divisors (69039035109267).

114301141113453 is a wasteful number, since it uses less digits than its factorization.

114301141113453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 286469025376.

The product of its (nonzero) digits is 8640, while the sum is 33.

Adding to 114301141113453 its reverse (354311141103411), we get a palindrome (468612282216864).

The spelling of 114301141113453 in words is "one hundred fourteen trillion, three hundred one billion, one hundred forty-one million, one hundred thirteen thousand, four hundred fifty-three".

Divisors: 1 3 7 19 21 57 133 399 286469025347 859407076041 2005283177429 5442911481593 6015849532287 16328734444779 38100380371151 114301141113453