11430433403411 has 16 divisors (see below), whose sum is σ = 12657464137728. Its totient is φ = 10234763220000.

The previous prime is 11430433403371. The next prime is 11430433403419.

11430433403411 is nontrivially palindromic in base 10.

It is a de Polignac number, because none of the positive numbers 2^k-11430433403411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11430433403419) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4143161 + ... + 6326661.

It is an arithmetic number, because the mean of its divisors is an integer number (791091508608).

Almost surely, 2^{11430433403411} is an apocalyptic number.

11430433403411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11430433403411 is a deficient number, since it is larger than the sum of its proper divisors (1227030734317).

11430433403411 is a wasteful number, since it uses less digits than its factorization.

11430433403411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2190682.

The product of its (nonzero) digits is 20736, while the sum is 32.

It can be divided in two parts, 1143043 and 3403411, that added together give a palindrome (4546454).

The spelling of 11430433403411 in words is "eleven trillion, four hundred thirty billion, four hundred thirty-three million, four hundred three thousand, four hundred eleven".