Base | Representation |
---|---|
bin | 10000101000101110100… |
… | …110010111011011000011 |
3 | 11001021220120121100220111 |
4 | 100220232212113123003 |
5 | 122212330214010313 |
6 | 2233110523252151 |
7 | 145411426045534 |
oct | 20505646273303 |
9 | 4037816540814 |
10 | 1143243110083 |
11 | 400934a276a8 |
12 | 16569997a057 |
13 | 83a65a11689 |
14 | 3d49468268b |
15 | 1eb1204e43d |
hex | 10a2e9976c3 |
1143243110083 has 2 divisors, whose sum is σ = 1143243110084. Its totient is φ = 1143243110082.
The previous prime is 1143243110039. The next prime is 1143243110159. The reversal of 1143243110083 is 3800113423411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1143243110083 - 225 = 1143209555651 is a prime.
It is not a weakly prime, because it can be changed into another prime (1143249110083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571621555041 + 571621555042.
It is an arithmetic number, because the mean of its divisors is an integer number (571621555042).
Almost surely, 21143243110083 is an apocalyptic number.
1143243110083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143243110083 is an equidigital number, since it uses as much as digits as its factorization.
1143243110083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 1143243110083 its reverse (3800113423411), we get a palindrome (4943356533494).
The spelling of 1143243110083 in words is "one trillion, one hundred forty-three billion, two hundred forty-three million, one hundred ten thousand, eighty-three".
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