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1143255034121 is a prime number
BaseRepresentation
bin10000101000101111010…
…011110110100100001001
311001021221102001011121112
4100220233103312210021
5122212341242042441
62233112031020105
7145411632310514
oct20505723664411
94037842034545
101143255034121
11400940731382
121656a196a635
1383a68327c15
143d4960a7d7b
151eb131074eb
hex10a2f4f6909

1143255034121 has 2 divisors, whose sum is σ = 1143255034122. Its totient is φ = 1143255034120.

The previous prime is 1143255034111. The next prime is 1143255034127. The reversal of 1143255034121 is 1214305523411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1020009102025 + 123245932096 = 1009955^2 + 351064^2 .

It is an emirp because it is prime and its reverse (1214305523411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1143255034121 - 210 = 1143255033097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1143255034127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571627517060 + 571627517061.

It is an arithmetic number, because the mean of its divisors is an integer number (571627517061).

Almost surely, 21143255034121 is an apocalyptic number.

It is an amenable number.

1143255034121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143255034121 is an equidigital number, since it uses as much as digits as its factorization.

1143255034121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 1143255034121 in words is "one trillion, one hundred forty-three billion, two hundred fifty-five million, thirty-four thousand, one hundred twenty-one".