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114330055254241 is a prime number
BaseRepresentation
bin11001111111101110001010…
…010101001010000011100001
3112222210211212010102121201211
4121333232022111022003201
5104441140423121113431
61043054300255230121
733040034231064301
oct3177561225120341
9488724763377654
10114330055254241
113347a116681452
12109a5b20218341
134ba437c8686a8
142033865cd1601
15d33ec176c2b1
hex67fb8a54a0e1

114330055254241 has 2 divisors, whose sum is σ = 114330055254242. Its totient is φ = 114330055254240.

The previous prime is 114330055254167. The next prime is 114330055254277. The reversal of 114330055254241 is 142452550033411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72919285839841 + 41410769414400 = 8539279^2 + 6435120^2 .

It is a cyclic number.

It is not a de Polignac number, because 114330055254241 - 219 = 114330054729953 is a prime.

It is a super-2 number, since 2×1143300552542412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114330055254194 and 114330055254203.

It is not a weakly prime, because it can be changed into another prime (114330055254841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57165027627120 + 57165027627121.

It is an arithmetic number, because the mean of its divisors is an integer number (57165027627121).

Almost surely, 2114330055254241 is an apocalyptic number.

It is an amenable number.

114330055254241 is a deficient number, since it is larger than the sum of its proper divisors (1).

114330055254241 is an equidigital number, since it uses as much as digits as its factorization.

114330055254241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 40.

The spelling of 114330055254241 in words is "one hundred fourteen trillion, three hundred thirty billion, fifty-five million, two hundred fifty-four thousand, two hundred forty-one".