Base | Representation |
---|---|
bin | 110101001111010011… |
… | …1001101110100010011 |
3 | 101221002212111110021021 |
4 | 1222132213031310103 |
5 | 3333122014330120 |
6 | 124304513340311 |
7 | 11155131630550 |
oct | 1523647156423 |
9 | 357085443237 |
10 | 114330230035 |
11 | 4453a48601a |
12 | 1a1a8b67697 |
13 | aa20671cb8 |
14 | 5768339a27 |
15 | 2e9234daaa |
hex | 1a9e9cdd13 |
114330230035 has 32 divisors (see below), whose sum is σ = 157153489920. Its totient is φ = 78219243648.
The previous prime is 114330230017. The next prime is 114330230039. The reversal of 114330230035 is 530032033411.
It is not a de Polignac number, because 114330230035 - 229 = 113793359123 is a prime.
It is a super-2 number, since 2×1143302300352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114330229991 and 114330230009.
It is not an unprimeable number, because it can be changed into a prime (114330230039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 38899596 + ... + 38902534.
It is an arithmetic number, because the mean of its divisors is an integer number (4911046560).
Almost surely, 2114330230035 is an apocalyptic number.
114330230035 is a deficient number, since it is larger than the sum of its proper divisors (42823259885).
114330230035 is a wasteful number, since it uses less digits than its factorization.
114330230035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5107.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 114330230035 its reverse (530032033411), we get a palindrome (644362263446).
The spelling of 114330230035 in words is "one hundred fourteen billion, three hundred thirty million, two hundred thirty thousand, thirty-five".
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