Base | Representation |
---|---|
bin | 11001111111101110100110… |
… | …101100100100110101110010 |
3 | 112222210220002021220220021111 |
4 | 121333232212230210311302 |
5 | 104441142411433432224 |
6 | 1043054415415343534 |
7 | 33040052100141055 |
oct | 3177564654446562 |
9 | 488726067826244 |
10 | 114330531155314 |
11 | 3347a340278a21 |
12 | 109a6033681baa |
13 | 4ba4427333766 |
14 | 20338ad1b2a9c |
15 | d33eed424d94 |
hex | 67fba6b24d72 |
114330531155314 has 4 divisors (see below), whose sum is σ = 171495796732974. Its totient is φ = 57165265577656.
The previous prime is 114330531155251. The next prime is 114330531155359. The reversal of 114330531155314 is 413551135033411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 86986866555625 + 27343664599689 = 9326675^2 + 5229117^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28582632788827 + ... + 28582632788830.
Almost surely, 2114330531155314 is an apocalyptic number.
114330531155314 is a deficient number, since it is larger than the sum of its proper divisors (57165265577660).
114330531155314 is an equidigital number, since it uses as much as digits as its factorization.
114330531155314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57165265577659.
The product of its (nonzero) digits is 162000, while the sum is 40.
Adding to 114330531155314 its reverse (413551135033411), we get a palindrome (527881666188725).
The spelling of 114330531155314 in words is "one hundred fourteen trillion, three hundred thirty billion, five hundred thirty-one million, one hundred fifty-five thousand, three hundred fourteen".
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