114331003321123 has 4 divisors (see below), whose sum is σ = 114456503874528. Its totient is φ = 114205502767720.

The previous prime is 114331003321103. The next prime is 114331003321141. The reversal of 114331003321123 is 321123300133411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114331003321123 - 2⁴¹ = 112131980065571 is a prime.

It is a super-2 number, since 2×114331003321123² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114331003321091 and 114331003321100.

It is not an unprimeable number, because it can be changed into a prime (114331003321103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62750275336 + ... + 62750277157.

It is an arithmetic number, because the mean of its divisors is an integer number (28614125968632).

Almost surely, 2^{114331003321123} is an apocalyptic number.

114331003321123 is a deficient number, since it is larger than the sum of its proper divisors (125500553405).

114331003321123 is an equidigital number, since it uses as much as digits as its factorization.

114331003321123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125500553404.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 114331003321123 its reverse (321123300133411), we get a palindrome (435454303454534).

The spelling of 114331003321123 in words is "one hundred fourteen trillion, three hundred thirty-one billion, three million, three hundred twenty-one thousand, one hundred twenty-three".