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11433114051001 is a prime number
BaseRepresentation
bin1010011001011111101010…
…1100111010000110111001
31111110222212101011010120121
42212113322230322012321
52444310004144113001
640152144452453241
72260005136652146
oct246277254720671
944428771133517
1011433114051001
113708835903a05
12134799291a221
1364c1a4331bc6
142b75195973cd
1514c60529d6a1
hexa65fab3a1b9

11433114051001 has 2 divisors, whose sum is σ = 11433114051002. Its totient is φ = 11433114051000.

The previous prime is 11433114050989. The next prime is 11433114051011. The reversal of 11433114051001 is 10015041133411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10000293080976 + 1432820970025 = 3162324^2 + 1197005^2 .

It is a cyclic number.

It is not a de Polignac number, because 11433114051001 - 215 = 11433114018233 is a prime.

It is not a weakly prime, because it can be changed into another prime (11433114051011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716557025500 + 5716557025501.

It is an arithmetic number, because the mean of its divisors is an integer number (5716557025501).

Almost surely, 211433114051001 is an apocalyptic number.

It is an amenable number.

11433114051001 is a deficient number, since it is larger than the sum of its proper divisors (1).

11433114051001 is an equidigital number, since it uses as much as digits as its factorization.

11433114051001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 11433114051001 its reverse (10015041133411), we get a palindrome (21448155184412).

The spelling of 11433114051001 in words is "eleven trillion, four hundred thirty-three billion, one hundred fourteen million, fifty-one thousand, one".