Base | Representation |
---|---|
bin | 1010011001011111101010… |
… | …1100111010000110111001 |
3 | 1111110222212101011010120121 |
4 | 2212113322230322012321 |
5 | 2444310004144113001 |
6 | 40152144452453241 |
7 | 2260005136652146 |
oct | 246277254720671 |
9 | 44428771133517 |
10 | 11433114051001 |
11 | 3708835903a05 |
12 | 134799291a221 |
13 | 64c1a4331bc6 |
14 | 2b75195973cd |
15 | 14c60529d6a1 |
hex | a65fab3a1b9 |
11433114051001 has 2 divisors, whose sum is σ = 11433114051002. Its totient is φ = 11433114051000.
The previous prime is 11433114050989. The next prime is 11433114051011. The reversal of 11433114051001 is 10015041133411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10000293080976 + 1432820970025 = 3162324^2 + 1197005^2 .
It is a cyclic number.
It is not a de Polignac number, because 11433114051001 - 215 = 11433114018233 is a prime.
It is not a weakly prime, because it can be changed into another prime (11433114051011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716557025500 + 5716557025501.
It is an arithmetic number, because the mean of its divisors is an integer number (5716557025501).
Almost surely, 211433114051001 is an apocalyptic number.
It is an amenable number.
11433114051001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11433114051001 is an equidigital number, since it uses as much as digits as its factorization.
11433114051001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 11433114051001 its reverse (10015041133411), we get a palindrome (21448155184412).
The spelling of 11433114051001 in words is "eleven trillion, four hundred thirty-three billion, one hundred fourteen million, fifty-one thousand, one".
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