Base | Representation |
---|---|
bin | 10101010011000011… |
… | …01101010011111001 |
3 | 1002111212022111112021 |
4 | 22221201231103321 |
5 | 141404113323231 |
6 | 5130332514441 |
7 | 553230264052 |
oct | 125141552371 |
9 | 32455274467 |
10 | 11434120441 |
11 | 4938298a17 |
12 | 227131ba21 |
13 | 1102b54553 |
14 | 7a67d7729 |
15 | 46dc42811 |
hex | 2a986d4f9 |
11434120441 has 2 divisors, whose sum is σ = 11434120442. Its totient is φ = 11434120440.
The previous prime is 11434120391. The next prime is 11434120469. The reversal of 11434120441 is 14402143411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7452005625 + 3982114816 = 86325^2 + 63104^2 .
It is an emirp because it is prime and its reverse (14402143411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11434120441 - 221 = 11432023289 is a prime.
It is a super-2 number, since 2×114341204412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11434100441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5717060220 + 5717060221.
It is an arithmetic number, because the mean of its divisors is an integer number (5717060221).
Almost surely, 211434120441 is an apocalyptic number.
It is an amenable number.
11434120441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11434120441 is an equidigital number, since it uses as much as digits as its factorization.
11434120441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11434120441 its reverse (14402143411), we get a palindrome (25836263852).
The spelling of 11434120441 in words is "eleven billion, four hundred thirty-four million, one hundred twenty thousand, four hundred forty-one".
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