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11434442215353 = 33811480738451
BaseRepresentation
bin1010011001100100100111…
…0111011100111110111001
31111111010021221022212112220
42212121021313130332321
52444320214201342403
640152524335554253
72260053065114343
oct246311167347671
944433257285486
1011434442215353
1137093575984a3
1213480a368b989
1364c35654b481
142b7603b2a293
1514c681ba3953
hexa6649ddcfb9

11434442215353 has 4 divisors (see below), whose sum is σ = 15245922953808. Its totient is φ = 7622961476900.

The previous prime is 11434442215331. The next prime is 11434442215453. The reversal of 11434442215353 is 35351224443411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11434442215353 - 216 = 11434442149817 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11434442215153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905740369223 + ... + 1905740369228.

It is an arithmetic number, because the mean of its divisors is an integer number (3811480738452).

Almost surely, 211434442215353 is an apocalyptic number.

It is an amenable number.

11434442215353 is a deficient number, since it is larger than the sum of its proper divisors (3811480738455).

11434442215353 is an equidigital number, since it uses as much as digits as its factorization.

11434442215353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3811480738454.

The product of its digits is 691200, while the sum is 42.

Adding to 11434442215353 its reverse (35351224443411), we get a palindrome (46785666658764).

The spelling of 11434442215353 in words is "eleven trillion, four hundred thirty-four billion, four hundred forty-two million, two hundred fifteen thousand, three hundred fifty-three".

Divisors: 1 3 3811480738451 11434442215353