Base | Representation |
---|---|
bin | 10101010011110001… |
… | …11100110111000011 |
3 | 1002112021210001120000 |
4 | 22221320330313003 |
5 | 141412143312233 |
6 | 5131111251043 |
7 | 553333131651 |
oct | 125170746703 |
9 | 32467701500 |
10 | 11440213443 |
11 | 494077a75a |
12 | 2273379a83 |
13 | 11041a8989 |
14 | 7a7541dd1 |
15 | 46e547d13 |
hex | 2a9e3cdc3 |
11440213443 has 20 divisors (see below), whose sum is σ = 17989161960. Its totient is φ = 7225396992.
The previous prime is 11440213441. The next prime is 11440213487. The reversal of 11440213443 is 34431204411.
11440213443 is a `hidden beast` number, since 1 + 1 + 4 + 4 + 0 + 213 + 443 = 666.
It is not a de Polignac number, because 11440213443 - 21 = 11440213441 is a prime.
It is a super-3 number, since 3×114402134433 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (11440213441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3715230 + ... + 3718307.
It is an arithmetic number, because the mean of its divisors is an integer number (899458098).
Almost surely, 211440213443 is an apocalyptic number.
11440213443 is a deficient number, since it is larger than the sum of its proper divisors (6548948517).
11440213443 is an equidigital number, since it uses as much as digits as its factorization.
11440213443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7433568 (or 7433559 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 11440213443 its reverse (34431204411), we get a palindrome (45871417854).
The spelling of 11440213443 in words is "eleven billion, four hundred forty million, two hundred thirteen thousand, four hundred forty-three".
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