Base | Representation |
---|---|
bin | 11010000000110011011111… |
… | …110100110111001100110011 |
3 | 120000001222000121000110122222 |
4 | 122000303133310313030303 |
5 | 104443400411020314021 |
6 | 1043152411551551255 |
7 | 33045311155440125 |
oct | 3200633764671463 |
9 | 500058017013588 |
10 | 114404504073011 |
11 | 334a8750036949 |
12 | 109b8438b2b52b |
13 | 4bab3b58a9889 |
14 | 20372c96cd215 |
15 | d35dcc70b6ab |
hex | 680cdfd37333 |
114404504073011 has 2 divisors, whose sum is σ = 114404504073012. Its totient is φ = 114404504073010.
The previous prime is 114404504072983. The next prime is 114404504073029. The reversal of 114404504073011 is 110370405404411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114404504073011 - 222 = 114404499878707 is a prime.
It is a super-2 number, since 2×1144045040730112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114404504075011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57202252036505 + 57202252036506.
It is an arithmetic number, because the mean of its divisors is an integer number (57202252036506).
Almost surely, 2114404504073011 is an apocalyptic number.
114404504073011 is a deficient number, since it is larger than the sum of its proper divisors (1).
114404504073011 is an equidigital number, since it uses as much as digits as its factorization.
114404504073011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 114404504073011 its reverse (110370405404411), we get a palindrome (224774909477422).
The spelling of 114404504073011 in words is "one hundred fourteen trillion, four hundred four billion, five hundred four million, seventy-three thousand, eleven".
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