Base | Representation |
---|---|
bin | 11010000000111011101000… |
… | …100110111001000111110011 |
3 | 120000002210120111201122021222 |
4 | 122000323220212321013303 |
5 | 104444021304240343103 |
6 | 1043200414545535255 |
7 | 33046040531125655 |
oct | 3200735046710763 |
9 | 500083514648258 |
10 | 114413241340403 |
11 | 33501423a98195 |
12 | 109ba07704452b |
13 | 4bac178aa9b95 |
14 | 20378b7c726d5 |
15 | d3623e7db638 |
hex | 680ee89b91f3 |
114413241340403 has 4 divisors (see below), whose sum is σ = 115006056062568. Its totient is φ = 113820426618240.
The previous prime is 114413241340381. The next prime is 114413241340421. The reversal of 114413241340403 is 304043142314411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114413241340403 - 238 = 114138363433459 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114413241340303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 296407360793 + ... + 296407361178.
It is an arithmetic number, because the mean of its divisors is an integer number (28751514015642).
Almost surely, 2114413241340403 is an apocalyptic number.
114413241340403 is a deficient number, since it is larger than the sum of its proper divisors (592814722165).
114413241340403 is an equidigital number, since it uses as much as digits as its factorization.
114413241340403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 592814722164.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 114413241340403 its reverse (304043142314411), we get a palindrome (418456383654814).
The spelling of 114413241340403 in words is "one hundred fourteen trillion, four hundred thirteen billion, two hundred forty-one million, three hundred forty thousand, four hundred three".
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