Base | Representation |
---|---|
bin | 110101010001111111… |
… | …0111011110111100011 |
3 | 101221100011001012202001 |
4 | 1222203332323313203 |
5 | 3333313101142201 |
6 | 124321452504431 |
7 | 11160304535512 |
oct | 1524376736743 |
9 | 357304035661 |
10 | 114420334051 |
11 | 44586328551 |
12 | 1a21317b117 |
13 | aa3622c39a |
14 | 57762b2679 |
15 | 2e9a1eb301 |
hex | 1aa3fbbde3 |
114420334051 has 2 divisors, whose sum is σ = 114420334052. Its totient is φ = 114420334050.
The previous prime is 114420334037. The next prime is 114420334099. The reversal of 114420334051 is 150433024411.
It is a weak prime.
It is an emirp because it is prime and its reverse (150433024411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114420334051 is a prime.
It is a super-3 number, since 3×1144203340513 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (114420332051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57210167025 + 57210167026.
It is an arithmetic number, because the mean of its divisors is an integer number (57210167026).
Almost surely, 2114420334051 is an apocalyptic number.
114420334051 is a deficient number, since it is larger than the sum of its proper divisors (1).
114420334051 is an equidigital number, since it uses as much as digits as its factorization.
114420334051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 114420334051 its reverse (150433024411), we get a palindrome (264853358462).
The spelling of 114420334051 in words is "one hundred fourteen billion, four hundred twenty million, three hundred thirty-four thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •