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114420334051 is a prime number
BaseRepresentation
bin110101010001111111…
…0111011110111100011
3101221100011001012202001
41222203332323313203
53333313101142201
6124321452504431
711160304535512
oct1524376736743
9357304035661
10114420334051
1144586328551
121a21317b117
13aa3622c39a
1457762b2679
152e9a1eb301
hex1aa3fbbde3

114420334051 has 2 divisors, whose sum is σ = 114420334052. Its totient is φ = 114420334050.

The previous prime is 114420334037. The next prime is 114420334099. The reversal of 114420334051 is 150433024411.

It is a weak prime.

It is an emirp because it is prime and its reverse (150433024411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114420334051 is a prime.

It is a super-3 number, since 3×1144203340513 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (114420332051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57210167025 + 57210167026.

It is an arithmetic number, because the mean of its divisors is an integer number (57210167026).

Almost surely, 2114420334051 is an apocalyptic number.

114420334051 is a deficient number, since it is larger than the sum of its proper divisors (1).

114420334051 is an equidigital number, since it uses as much as digits as its factorization.

114420334051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 114420334051 its reverse (150433024411), we get a palindrome (264853358462).

The spelling of 114420334051 in words is "one hundred fourteen billion, four hundred twenty million, three hundred thirty-four thousand, fifty-one".