Base | Representation |
---|---|
bin | 10101010100000111… |
… | …01010001001110011 |
3 | 1002112111001122222111 |
4 | 22222003222021303 |
5 | 141413403123103 |
6 | 5131251350151 |
7 | 553366032343 |
oct | 125203521163 |
9 | 32474048874 |
10 | 11443020403 |
11 | 4942317661 |
12 | 22742b2357 |
13 | 110494c4b9 |
14 | 7a7a72d23 |
15 | 46e8ee86d |
hex | 2aa0ea273 |
11443020403 has 2 divisors, whose sum is σ = 11443020404. Its totient is φ = 11443020402.
The previous prime is 11443020397. The next prime is 11443020437. The reversal of 11443020403 is 30402034411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11443020403 is a prime.
It is not a weakly prime, because it can be changed into another prime (11443020493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5721510201 + 5721510202.
It is an arithmetic number, because the mean of its divisors is an integer number (5721510202).
Almost surely, 211443020403 is an apocalyptic number.
11443020403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11443020403 is an equidigital number, since it uses as much as digits as its factorization.
11443020403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 11443020403 its reverse (30402034411), we get a palindrome (41845054814).
The spelling of 11443020403 in words is "eleven billion, four hundred forty-three million, twenty thousand, four hundred three".
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