1144302201331 has 4 divisors (see below), whose sum is σ = 1204528633000. Its totient is φ = 1084075769664.

The previous prime is 1144302201319. The next prime is 1144302201337. The reversal of 1144302201331 is 1331022034411.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1144302201331 - 2⁵ = 1144302201299 is a prime.

It is a super-2 number, since 2×1144302201331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1144302201296 and 1144302201305.

It is not an unprimeable number, because it can be changed into a prime (1144302201337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30113215806 + ... + 30113215843.

It is an arithmetic number, because the mean of its divisors is an integer number (301132158250).

Almost surely, 2^{1144302201331} is an apocalyptic number.

1144302201331 is a deficient number, since it is larger than the sum of its proper divisors (60226431669).

1144302201331 is an equidigital number, since it uses as much as digits as its factorization.

1144302201331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60226431668.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1144302201331 its reverse (1331022034411), we get a palindrome (2475324235742).

The spelling of 1144302201331 in words is "one trillion, one hundred forty-four billion, three hundred two million, two hundred one thousand, three hundred thirty-one".