Base | Representation |
---|---|
bin | 10000101001101111011… |
… | …000100001011011011011 |
3 | 11001101201022210002200222 |
4 | 100221233120201123123 |
5 | 122222041440000331 |
6 | 2233410431150255 |
7 | 145450364340215 |
oct | 20515730413333 |
9 | 4041638702628 |
10 | 1144330000091 |
11 | 4013424a8203 |
12 | 16594197538b |
13 | 83ba9c52065 |
14 | 3d558b6b5b5 |
15 | 1eb77695b7b |
hex | 10a6f6216db |
1144330000091 has 2 divisors, whose sum is σ = 1144330000092. Its totient is φ = 1144330000090.
The previous prime is 1144330000061. The next prime is 1144330000097. The reversal of 1144330000091 is 1900000334411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1144330000091 - 226 = 1144262891227 is a prime.
It is a super-2 number, since 2×11443300000912 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1144330000091.
It is not a weakly prime, because it can be changed into another prime (1144330000097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572165000045 + 572165000046.
It is an arithmetic number, because the mean of its divisors is an integer number (572165000046).
Almost surely, 21144330000091 is an apocalyptic number.
1144330000091 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144330000091 is an equidigital number, since it uses as much as digits as its factorization.
1144330000091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 26.
The spelling of 1144330000091 in words is "one trillion, one hundred forty-four billion, three hundred thirty million, ninety-one", and thus it is an aban number.
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