Base | Representation |
---|---|
bin | 11010000001001110001010… |
… | …110101101111011011011010 |
3 | 120000011200221111020021000020 |
4 | 122001032022311233123122 |
5 | 104444333034102323114 |
6 | 1043213505443451310 |
7 | 33050343650416221 |
oct | 3201161265573332 |
9 | 500150844207006 |
10 | 114433143011034 |
11 | 33509906a66971 |
12 | 10a01ab0086b36 |
13 | 4bb0ccaca7553 |
14 | 203884507dcb8 |
15 | d36a06ad2aa9 |
hex | 68138ad6f6da |
114433143011034 has 64 divisors (see below), whose sum is σ = 241708311097344. Its totient is φ = 36044251618496.
The previous prime is 114433143011021. The next prime is 114433143011093. The reversal of 114433143011034 is 430110341334411.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 114433143010986 and 114433143011004.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 203680852 + ... + 204241904.
It is an arithmetic number, because the mean of its divisors is an integer number (3776692360896).
Almost surely, 2114433143011034 is an apocalyptic number.
114433143011034 is an abundant number, since it is smaller than the sum of its proper divisors (127275168086310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114433143011034 is a wasteful number, since it uses less digits than its factorization.
114433143011034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 578971.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 114433143011034 its reverse (430110341334411), we get a palindrome (544543484345445).
The spelling of 114433143011034 in words is "one hundred fourteen trillion, four hundred thirty-three billion, one hundred forty-three million, eleven thousand, thirty-four".
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