Base | Representation |
---|---|
bin | 10101010100001001… |
… | …11001001100000011 |
3 | 1002112111200010001102 |
4 | 22222010321030003 |
5 | 141413444003011 |
6 | 5131302325015 |
7 | 553401551222 |
oct | 125204711403 |
9 | 32474603042 |
10 | 11443344131 |
11 | 49425188aa |
12 | 227442976b |
13 | 1104a3395b |
14 | 7a7b18cb9 |
15 | 46e96573b |
hex | 2aa139303 |
11443344131 has 4 divisors (see below), whose sum is σ = 11604518064. Its totient is φ = 11282170200.
The previous prime is 11443344119. The next prime is 11443344161. The reversal of 11443344131 is 13144334411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11443344131 - 226 = 11376235267 is a prime.
It is a super-2 number, since 2×114433441312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11443344094 and 11443344103.
It is not an unprimeable number, because it can be changed into a prime (11443344161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80586860 + ... + 80587001.
It is an arithmetic number, because the mean of its divisors is an integer number (2901129516).
Almost surely, 211443344131 is an apocalyptic number.
11443344131 is a deficient number, since it is larger than the sum of its proper divisors (161173933).
11443344131 is an equidigital number, since it uses as much as digits as its factorization.
11443344131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161173932.
The product of its digits is 6912, while the sum is 29.
Adding to 11443344131 its reverse (13144334411), we get a palindrome (24587678542).
The spelling of 11443344131 in words is "eleven billion, four hundred forty-three million, three hundred forty-four thousand, one hundred thirty-one".
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