114440113 has 2 divisors, whose sum is σ = 114440114. Its totient is φ = 114440112.

The previous prime is 114440099. The next prime is 114440147. The reversal of 114440113 is 311044411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74787904 + 39652209 = 8648^2 + 6297^2 .

It is an emirp because it is prime and its reverse (311044411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114440113 - 2⁹ = 114439601 is a prime.

It is not a weakly prime, because it can be changed into another prime (114440153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57220056 + 57220057.

It is an arithmetic number, because the mean of its divisors is an integer number (57220057).

Almost surely, 2^114440113 is an apocalyptic number.

It is an amenable number.

114440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

114440113 is an equidigital number, since it uses as much as digits as its factorization.

114440113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 114440113 is about 10697.6685777790. The cubic root of 114440113 is about 485.5039407173.

Adding to 114440113 its reverse (311044411), we get a palindrome (425484524).

The spelling of 114440113 in words is "one hundred fourteen million, four hundred forty thousand, one hundred thirteen".