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11444366547881 is a prime number
BaseRepresentation
bin1010011010001001100101…
…1001110001101110101001
31111112001220120201012102022
42212202121121301232221
53000001030314013011
640201245220514225
72260554033416411
oct246423131615651
944461816635368
1011444366547881
11371258a620403
121349bb324b975
13650278664597
142b7ca5bd3641
1514ca630b68db
hexa6899671ba9

11444366547881 has 2 divisors, whose sum is σ = 11444366547882. Its totient is φ = 11444366547880.

The previous prime is 11444366547869. The next prime is 11444366547937. The reversal of 11444366547881 is 18874566344411.

11444366547881 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8405128705600 + 3039237842281 = 2899160^2 + 1743341^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11444366547881 is a prime.

It is a super-2 number, since 2×114443665478812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11444366547811) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5722183273940 + 5722183273941.

It is an arithmetic number, because the mean of its divisors is an integer number (5722183273941).

Almost surely, 211444366547881 is an apocalyptic number.

It is an amenable number.

11444366547881 is a deficient number, since it is larger than the sum of its proper divisors (1).

11444366547881 is an equidigital number, since it uses as much as digits as its factorization.

11444366547881 is an evil number, because the sum of its binary digits is even.

The product of its digits is 61931520, while the sum is 62.

The spelling of 11444366547881 in words is "eleven trillion, four hundred forty-four billion, three hundred sixty-six million, five hundred forty-seven thousand, eight hundred eighty-one".