Base | Representation |
---|---|
bin | 10101010100010010… |
… | …00011000011011001 |
3 | 1002112120201102212002 |
4 | 22222021003003121 |
5 | 141414233324423 |
6 | 5131341530345 |
7 | 553414035131 |
oct | 125211030331 |
9 | 32476642762 |
10 | 11444433113 |
11 | 49430a1a93 |
12 | 22748739b5 |
13 | 1105025519 |
14 | 7a7d1dac1 |
15 | 46eacd228 |
hex | 2aa2430d9 |
11444433113 has 4 divisors (see below), whose sum is σ = 11449810740. Its totient is φ = 11439055488.
The previous prime is 11444433071. The next prime is 11444433139. The reversal of 11444433113 is 31133444411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7430957209 + 4013475904 = 86203^2 + 63352^2 .
It is a cyclic number.
It is not a de Polignac number, because 11444433113 - 222 = 11440238809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11444435113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2685620 + ... + 2689877.
It is an arithmetic number, because the mean of its divisors is an integer number (2862452685).
Almost surely, 211444433113 is an apocalyptic number.
It is an amenable number.
11444433113 is a deficient number, since it is larger than the sum of its proper divisors (5377627).
11444433113 is an equidigital number, since it uses as much as digits as its factorization.
11444433113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5377626.
The product of its digits is 6912, while the sum is 29.
Adding to 11444433113 its reverse (31133444411), we get a palindrome (42577877524).
The spelling of 11444433113 in words is "eleven billion, four hundred forty-four million, four hundred thirty-three thousand, one hundred thirteen".
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